我用的是tiny210v2的开发板,我想用p4口的1,3,5,7,9,11,13,15(即gpj0(0)~gpj0(7))这8个引脚作一个led指示灯的驱动,我动态加载驱动模块调试时没问题,可以正常使用,静态加载到内核里时可以生成设备节点,调试时调试程序没报错但引脚就是没反应,我也换过两个核心板试过一样的问题。这8个引脚是核心板上留给我们开发的,原来是cam—b模块的,还有cam—a已经连在底板上使用了,会不会是友善之臂在内核中添加的摄像头驱动占用了这几个口(这个驱动他还不提供源代码),我测量这几个引脚时会有0.7~1.4的电平。
led驱动,测试程序如下:(驱动应该没问题)
#include <linux/kernel.h>
#include <linux/module.h>
#include <linux/miscdevice.h>
#include <linux/fs.h>
#include <linux/types.h>
#include <linux/moduleparam.h>
#include <linux/slab.h>
#include <linux/ioctl.h>
#include <linux/cdev.h>
#include <linux/delay.h>
#include <mach/gpio.h>
#include <mach/regs-gpio.h>
#include <plat/gpio-cfg.h>
#define DEVICE_NAME "my_leds1"
static int led_gpios[] = {
S5PV210_GPJ0(0),
S5PV210_GPJ0(1),
S5PV210_GPJ0(2),
S5PV210_GPJ0(3),
S5PV210_GPJ0(4),
S5PV210_GPJ0(5),
S5PV210_GPJ0(6),
S5PV210_GPJ0(7),
};
#define LED_NUM ARRAY_SIZE(led_gpios)
static long mini210_leds_ioctl(struct file *filp, unsigned int cmd,
unsigned long arg)
{
switch(cmd) {
case 0:
case 1:
if (arg > LED_NUM) {
return -EINVAL;
}
gpio_set_value(led_gpios[arg], !cmd);
//printk(DEVICE_NAME": %d %d\n", arg, cmd);
break;
default:
return -EINVAL;
}
return 0;
}
static struct file_operations mini210_led_dev_fops = {
.owner = THIS_MODULE,
.unlocked_ioctl = mini210_leds_ioctl,
};
static struct miscdevice mini210_led_dev = {
.minor = MISC_DYNAMIC_MINOR,
.name = DEVICE_NAME,
.fops = &mini210_led_dev_fops,
};
static int __init mini210_led_dev_init(void) {
int ret;
int i;
for (i = 0; i < LED_NUM; i++) {
ret = gpio_request(led_gpios, "my_LED");
if (ret) {
printk("%s: request GPIO %d for LED failed, ret = %d\n", DEVICE_NAME,
led_gpios, ret);
return ret;
}
s3c_gpio_cfgpin(led_gpios, S3C_GPIO_OUTPUT);
gpio_set_value(led_gpios, 1);
}
ret = misc_register(&mini210_led_dev);
printk(DEVICE_NAME"\tinitialized\n");
return ret;
}
static void __exit mini210_led_dev_exit(void) {
int i;
for (i = 0; i < LED_NUM; i++) {
gpio_free(led_gpios);
}
misc_deregister(&mini210_led_dev);
}
module_init(mini210_led_dev_init);
module_exit(mini210_led_dev_exit);
MODULE_LICENSE("GPL");
测试程序如下:
#include<stdio.h>
#include<fcntl.h>
#include<unistd.h>
main()
{
int fd;
int i;
if((fd = open("/dev/my_leds1",O_RDWR,777)) < 0)
{
printf("open my_leds failed\n");
return 0;
}
while(1){
for(i = 0; i < 8; i++)
{
ioctl(fd,1,i);
}
sleep(3);
for(i = 0; i < 8; i++)
{
ioctl(fd,0,i);
}
sleep(1);
}
}