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 <title><![CDATA[想要轮流采集两个摄像头，求大大帮忙]]></title>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384]]></link>
 <description><![CDATA[Latest 20 replies of 想要轮流采集两个摄像头，求大大帮忙]]></description>
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 <description><![CDATA[有一个ioctl是可以控制摄像头的采集！！！！,STREAMOFF]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#119030]]></link>
 <author><![CDATA[12555]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Wed, 21 Sep 2011 05:49:40 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[摄像头采集，MARK!]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#118970]]></link>
 <author><![CDATA[changhui0222]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Wed, 21 Sep 2011 02:09:46 +0000]]></pubdate>
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 <title><![CDATA[回 3楼(lxm0603) 的帖子]]></title>
 <description><![CDATA[嗯，我大概弄出来就是设计按钮，点的时候实现打开这个摄像头关闭那个摄像头并建立映射，虽然比较麻烦，但是稍微还行……]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#87343]]></link>
 <author><![CDATA[henry012]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Wed, 25 May 2011 01:30:48 +0000]]></pubdate>
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 <description><![CDATA[你这具体的代码发上来吧~]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#85852]]></link>
 <author><![CDATA[lxm0603]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Fri, 20 May 2011 11:42:30 +0000]]></pubdate>
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 <title><![CDATA[回 1楼(huhu2207) 的帖子]]></title>
 <description><![CDATA[我也是硬要搞两个交差啊，其实就是个循环吧，我不会写……]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#85010]]></link>
 <author><![CDATA[henry012]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Wed, 18 May 2011 00:39:10 +0000]]></pubdate>
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 <description><![CDATA[俺一个还没搞明白呢………… [s:6]]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=12384#84924]]></link>
 <author><![CDATA[huhu2207]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Tue, 17 May 2011 11:03:30 +0000]]></pubdate>
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