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 <title><![CDATA[求解 SD的寿命]]></title>
 <link><![CDATA[http://121.40.142.80/read.php?tid=23993]]></link>
 <description><![CDATA[Latest 20 replies of 求解 SD的寿命]]></description>
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 <description><![CDATA[比如1条记录占1K,2800条就是2.8M,30天也就65.6M,2G的flash,你要用30个月才循环一次,你循环1w次,30w个月,还不够你用么?]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=23993#201914]]></link>
 <author><![CDATA[piaoroumi]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Mon, 15 Oct 2012 01:05:54 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[求解释！！！]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=23993#201849]]></link>
 <author><![CDATA[刘子]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Sun, 14 Oct 2012 11:49:51 +0000]]></pubdate>
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 <description><![CDATA[这个应该是指同一个地址读写10w次吧,如果你的数据是按地址依次写入,即用sd卡的空间来换取次数的话,应该是可以解决的...]]></description>
 <link><![CDATA[http://121.40.142.80/read.php?tid=23993#200743]]></link>
 <author><![CDATA[piaoroumi]]></author>
 <category><![CDATA[Linux技术交流区]]></category>
 <pubdate><![CDATA[Mon, 08 Oct 2012 00:50:01 +0000]]></pubdate>
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