tiny 6410裸机按键中断进不了中断求大神指点

程序参照网上的基本没有差别，实在找不出是哪里的问题，还望指教，初始化函数如下：
void INTC_Init()
{
  
  
     rGPNCON = (rGPNCON & ~(0xfffU)) | 0xaaa; //k1,k2,k3,k4,k5,k6中断方式
    rGPLCON1 = (rGPLCON1 & ~(0xff<<12)) | (0x33<<12);//k7,k8


    rEINT0CON0 =(rEINT0CON0 & ~(0xfffU)) |0x222;  //k1,k2,k3,k4,k5,k6下降沿触发
    rEINT0CON1 =(rEINT0CON1 & ~(0xff<<4)) |(0x22<<4);//k7,k8下降沿触发

    rEINT0FLTCON0 |=0x00C0C0C0;//使能过滤器 EINT0,1,2,3,4,5选择数字滤波器
    rEINT0FLTCON2 |=0x00C0C000;//使能过滤器 EINT19，20选择数字滤波器
    
    rEINT0MASK = ~（0x18003f）;   //中断使能,开中断
    rEINT0PEND = 0x18003f;            
  
   //中断选择寄存器，是置为IRQ 还是FRQ
   rVIC0INTSELECT &=0xFFFFFFFE;  //设置IRQ模式，其实可以不设，上电自动复位
  
   VIC0VECTADDR_00=(unsigned)KeyIntHandle;//KeyIntHandle为中断处理函数
   VIC0VECTADDR_01=(unsigned)KeyIntHandle;
   VIC1VECTADDR_32=(unsigned)KeyIntHandle;
   VIC1VECTADDR_33=(unsigned)KeyIntHandle;
  
   //配置中断使能寄存器  GPN0,1,2,3,4,5为EINT0,1,2,3,4,5属于VIC0,对应于VIC0中的00,01寄存器,GPL11,12为EINT19,20属于VIC1中的32,33寄存器
   rVIC0INTENABLE |=0x00000003 ;
   rVIC1INTENABLE |=0x00000003 ;
    
  
}